Find the required angular speed, ω, of an ultracentrifuge for the radial acceleration of a point 2.10 cm from the axis to equal 5.00×105 g (where g is the free-fall acceleration)

ω = 15275.25 rad/s

Explanation:

Given that,

Radial acceleration of an ultracentrifuge is,

Distance from the axis, r = 2.1 cm = 0.021 m

g is the free-fall acceleration such that g = 9.8 m/s²

We need to find the angular speed of an ultracentrifuge. The formula that is used to find the angular speed is given by formula as follows :

Putting all the values,

So, the required angular speed, ω, of an ultracentrifuge is 15275.25 rad/s.

iron would move it is magnetic there is a mag field around the current in the wire

current flows in a wire