Calculate the acceleration of a 2000-kg single engine airplane just before takeoff when the thrust of its engine is 500 n

Acceleration (m/s^2) = Force (N) divided by Mass (kg)

Acceleration = 500 / 2000 = 0.25 m/s^2

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

Answer8.0m;