3- The velocity-time graph below shows the motion of a ball in free fall. What is the acceleration of the ball from
0.5 to 0.7 seconds? Show your work:

The acceleration of the ball from 0.5 to 0.7 seconds is 10 m/s²

Explanation:

The data from the given velocity-time graph are as follows;

Velocity (meters per second)                             Time (seconds)

0                                                                              0.4

0.5                                                                          0.45

1.                                                                             0.5

1.5                                                                           0.55

2.2                                                                          0.6

2.5                                                                          0.65

3.0                                                                          0.7

3.5                                                                          0.75

4.0                                                                          0.8

4.5                                                                          0.85

Therefore, the average acceleration of the ball from 0.7 to 0.7 seconds is given as follows;

Acceleration = (Change in velocity)/(Related change in time)

Acceleration = (3.0 - 1)m/s/(0.7 - 0.5)s = 2/0.2 m/s²  = 10 m/s²

The acceleration of the ball from 0.5 to 0.7 seconds = 10 m/s².

d

explanation:

v=uf/(u-f)

= 5.10/(5-10) convex lens has positive focal length

=50/-5

=-10 cm (formed at other side)