In determining the percentage purity of an impure NaCo3 for 4.2g of the impure was place in measuring cylinder to work up to 1000cm . the resultant solution is neutralize by 0.092m of 20.40cm3 Hcl in lab [ na=23,o= 16, c=12, h=1, cl=35-5] hint: percentage purity =mass pure substance ×100
mass concentrate : impure substance??

The answer is c hope this

Distance covered = speed x timethe distance traveled going against the stream = distance traveled with the stream.therefore it is the speed and the time that are the variables.as he travels the same distance both ways, speed x time is the same for each way.going upstream his speed is 4 kph; going downstream his speed is 6 kph.therefore we have two simultaneous equations: time upstream x 4 = time downstream x 6time upstream + time downstream = 60 minutestherefore we have the equation: time upstream = 6/10 hour, time downstream therefore = 4/10 hour.distance traveled at 4km/hr in 6/10 hour = 24/10 = 2.4km.check: distance traveled at 6km/hr in 4/10 hour = 24/10 = 2.4km.

20hope i helep