A car travels at a constant speed around a circular track whose radius is 3.22 km. The car goes once around the track in 248 s. What is the magnitude of the centripetal acceleration of the car

a = 1,838.17m/s²

Explanation:

centripetal acceleration a = v²/r

v is velocity of the car

r is the radius = 3.22km = 3220m

time t = 248

First is to find to velocity using the equation of motion:

v = u+gt

v = 0+(9.81)(248)

v = 2,432.88m/s

a = 2,432.88²/3220

a = 5,918,905.0944/3220

a = 1,838.17m/s²

The magnitude of the centripetal acceleration of the car is 1,838.17m/s²

it's when something is going so fast it makes a loud noise, breaking the sound barrier, for example: a jet makes a loud noise, not only cause of the jet but because they reached a point where they went so fast that you can year the noise from various parts, kinda like a police car, lets say the car was going   so fast that you hear the siren of the cop car right next to you, but the car is probably a mile a way, it's cos the siren was next to you a few seconds if you understand me

the answer to this is proletariats.

hope this : )