10.0 mF parallel-plate capacitor with circular plates is connected to a 12.0 V battery. (a) What is the charge on each plate

0.12 C.

Explanation:

The following data were obtained from the question:

Capacitor (C) = 10 mF

Potential difference (V) = 12 V

Charge (Q) =?

Next, we shall convert 10 mF to farad (F). This can be obtained as follow:

1 mF = 1×10¯³ F

Therefore,

10 mF = 10 mF × 1×10¯³ F/ 1mF

10 mF = 0.01 F

Therefore, 10 mF is equivalent to 0.01 F.

Finally, we shall determine the charge on the capacitor as illustrated below:

Capacitor (C) = 0.01 F

Potential difference (V) = 12 V

Charge (Q) =?

Q = CV

Q = 0.01 × 12

Q = 0.12 C

Therefore, the charge on the capacitor is 0.12 C.

like poles repel so keep pushing north to north and repels funny to see this

air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.