Adrowsy cat spots a flowerpot that sails first up and then down past an open window. the pot was in view for a total of 0.51 s, and the top-to-bottom height of the window is 2.25 m. how high above the window top did the flowerpot go?

The pot spends T = 0.185s going up and 0.185s going down past the window. 
The average speed passing by the window is 2.20 m/0.185s = 11.89 m/s. 
During passage, the pot increases speed by T*g = 0.185*9.81 = 1.815 m/s 
The speed is therefore 12.80 m/s at the bottom of the window and 10.98 m/s at the top of the window. 

The 10.98 m/s speed at the top of the window allows it to rise another 10.98^2/(2g)= 6.15 m past the top of the window

explanation:

could i give you a exaplo that could you?

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