a tractor drags 281kg plow across a field at a constant 3.3m/s. if the coefficient of friction between the plow and the ground is 0.440, how much force does the tractor apply to the plow?

a

explanation:

because they are cartillidge

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west