An electric bulb connected in 220 volt supply line draw a current of 0.05 ampere calculate the amount of coulomb second following through the bulb

Q = 0.05 [C]

Explanation:

To be able to determine the load we must first determine the power by means of ohm's law:

P = V*I

where:

P = power [W]

V = volts [V]

I = amperes [amp]

P = 220*0.05

P = 11 [W]

Now as we have a power value, we know that power is defined as work in unit time, i.e. Joules over second is the equivalent of Watts.

P = w/t

where:

w = work [J]

t = time = 1 [s]

w = 11*1

w = 11 [J]

Finally, if we want to know how much charge was involved, we use:

Q = w/V

where:

Q = charge [coulumbs]

w = work = 11 [J]

V = volts = 220 [V]

Q = 11/220

Q = 0.05 [C]

i don't understand. explain it clearly

answer; how far out of place which the object finished relative to the starting location;