Two blocks, stacked one on top of the other, slide on a frictionless horizontal surface. The surface between the two blocks is rough, however, with a coefficient of static friction equal to 0.40. The top block has a mass of 2.9 kg, and the bottom block's mass is 5.8 kg. If a horizontal force F is applied to the bottom block, what is the maximum value F can have before the top block begins to slip?

The value is

Explanation:

From the question we are told that

    The coefficient of static friction is  

    The mass of the top of block  is  

     The mass of the  bottom is  

Generally given that the frictional force between the bottom block and the frictionless horizontal is zero then the maximum value F can have before the top block begins to slip will be equal to the frictional force between the top and  the bottom block which is mathematically represented as

Here N is the normal force acting on top block which is mathematically represented as

=>

So

=>  

i think they are all correct

explanation:

they seem good