A 0.52-kg block sits on a lab table. There is a forward force of 2.63 N and a force backwards of 0.67 N. What is the acceleration of the block?

a = 3.77 m/s²

Explanation:

Given:

m = 0.52-kg

F = 2.63 N - 0.67 N = 1.96 N (Net Force)

Unknown:

a or acceleration

Formula and solution:

a = F/m

a = 1.96 kg.m/s² ÷ 0.52 kg

Final

a = 3.77 m/s²

There are the same unit in the solution which is kg so we cancel it then the rest which is m/s² combine it in the quotient of 1.96 kg.m/s² or N and 0.52 kg which is 3.769 then round off to nearest hundredths so the final answer is 3.77 m/s²

if the thermos has a vacuum innner, then heat through conv currents and conduction are reduced = vacuum flask

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg