A cyclist is riding a bike with an initial speed of 4 m/s and accelerates uniformly at 2 m second squared in the same direction of its motion along the street what is the speed of the cyclist after traveling 6 m ?

6.32m/s

Explanation:

Given parameters:

Initial velocity  = 4m/s

Acceleration  = 2m/s²

Distance covered  = 6m

Unknown:

Final velocity  = ?

Solution:

To solve this problem, we have to apply the appropriate motion equation;

         V²  = U² + 2aS

where V is final speed

          U is the initial speed

         a is the acceleration

          S is the distance

Insert the given parameters and solve;

      V² = 4² + 2 x 2 x 6

      V² = 16 + 24

      V² = 40

       V = √40 = 6.32m/s

the answer to this question is 60 n