A proton in a cyclotron has a velocity of 2x108 m/s, which is nearly the speed of light. The uncertainty in the velocity is 1%. What is the minimum uncertainty in the position of the proton in meters

The minimum uncertainty in the position of the proton is 1.578 x 10⁻¹⁴ m

Explanation:

Given;

velocity of the proton, v = 2 x 10⁸ m/s

uncertainty in the velocity, = 1 % = 0.01 v = 0.01 x 2 x 10⁸ m/s = 2 x 10⁶ m/s

The momentum of the proton is given by;

ΔP = mv = (1.67 x 10⁻²⁷)(2 x 10⁶ ) = 3.34 x 10⁻²¹ kgm/s

The minimum uncertainty in the position of the proton is given by;

Therefore, the minimum uncertainty in the position of the proton is 1.578 x 10⁻¹⁴ m

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weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards