two cars A and B are 600 meters apart car A travels due east at some speed per on a collision course with car b which travels due west at half speed as car A if the two cars fatally collide with each other in 5 seconds how fast was car A going?

Car A was going at 80 m/s

Explanation:

Let's call "x" the unknown speed of car A. In such case, the speed of car B would be x/2.

We proceed to describe the distance covered by car A (dA) in the 5 seconds it took to collide:  dA = speed * time = x * 5 = 5 x

Now the distance covered by car B (dB) in the same time would be:

dB = speed * time = (x/2) * 5 = 5 x / 2

Now, we know that the distance that separated both cars was 600 meters, so the addition of what car A covered plus what car B covered must equal 600 m, and in equation form:

dA + dB = 600

5 x + 5 x / 2 = 600

combining like terms:

15 x / 2 = 600

multiplying both sides by 2:

15 x = 1200

divide both sides by 15:

x = 80 m/s

This is the speed of car A.

the entire statement is true and correct.  

there's no diagram, nothing is illustrated, and no question is asked.

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .