HELP ME Two particles are separated by 0.38 m and have charges of -6.25*10-9 C and
2.91 x 10-9 C. Use Coulomb's law to predict the force between the particles if
the distance is doubled. The equation for Coulomb's law is Fe = kq,92, and
the constant, k, equals 9.00 x 10°Nm2c2

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s