Mick drove the 1 mile distance to his place of work at 30 mph. If Mick wanted to average 60 mph on his round trip, (home to work and then back home) how fast would he have to travel on his way home? (The answer is not 90 mph)

I believe the answer is 30mph because if it is a 2-way trip then he would travel the same speed as the first trip. (sorry if this is wrong)

Explanation:

Hope this helps :)

option number c is the right answer.

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j