A Penny is dropped and falls freely from the top of the Empire State building 443m high. What information do you know? 1b. How long does it take to hit the ground? 1c. How fast is it moving right before it hits the ground?

1b. 9.51 s

1c. 93.18 m/s.

Explanation:

1a. From the question given above, the following data were obtained:

Initial velocity (u) = 0 m/s

Height (h) = 443 m

Acceleration due to gravity (g) = 9.8 m/s²

1b. Determination of the time it takes for the penny to get to the ground.

Height (h) = 443 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

h = ½gt²

443 = ½ × 9.8 × t²

443 = 4.9 × t²

Divide both side by 4.9

t² = 443/4.9

Take the square root of both side

t = √(443/4.9)

t = 9.51 s

1c. Determination of the speed of the penny before it hits the ground.

Initial velocity (u) = 0 m/s

Height (h) = 443 m

Acceleration due to gravity (g) = 9.8 m/s²

Final velocity (v) =.?

v² = u² + 2gh

v² = 0² + 2 × 9.8 × 443

v² = 0 + 8682.8

v² = 8682.8

Take the square root of both side

v = √8682.8

v = 93.18 m/s

answer: the exterior temperature of commercial jet planes as they leave the stratosphere and return to the ground increases steadily.

explanation:

the lower most layer of atmosphere is troposphere which extends from 0 to 12 km above the surface of the earth. the temperature initially decreases as distance is increased from the earth's surface. commercial jets fly in lower part of the stratosphere. the stratosphere extends upto 50 km. the temperature in stratosphere starts rising again due to presence of ozone which traps the uv rays.

thus, when the planes leave the stratosphere and return to the ground, the exterior temperature increases steadily.