A cat leaps to try to catch a bird. If the cat's jump was at 60° off the ground and its initial velocity was 60 m/s what is the highest point of its trajectory, neglecting air resistance?

137.75 m

Explanation:

The following data were obtained from the question:

Angle of projection (θ) = 60°

Initial velocity (u) = 60 m/s

Acceleration due to gravity (g) = 9.8 m/s²

Maximum height (H) =.?

The maximum height reached by the car can be obtained as follow:

H = u² Sine²θ /2g

H = 60² × (Sine 60)² / 2 × 9.8

H = 3600 × 0.866² / 19.6

H = 137.75 m

Therefore, the maximum height reached by the cat is 137.75 m