A marble rolls off a ledge with an initial velocity of (1.125m/s, 0o). The marble lands 0.45m from the base of the ledge. Calculate the magnitude of the velocity, in m/s, of the marble just before it lands. I don't want the answer but can someone please describe to me how I'm supposed to solve this and the variables I need.

3.2m/s

Explanation:

Given parameters:

Initial velocity  = 1.125m/s

Height of fall  = 0.45m

Unknown:

Final velocity  = ?

Solution:

To solve this problem, we have to look at our given parameters and compare to the appropriate motion equation.

  we have been given;   u (initial velocity) and height of fall (h)

Since this body falls under acceleration due to gravity, g = 9.8m/s²

Now, we use;

           V²  = U² + 2gh

 where V is the final velocity

       Input the parameters and solve;

          V² = 1.125² + (2 x 9.8 x 0.45)

          V = 3.2m/s