A centrifuge in a medical laboratory rotates at an angular speed of 3,550 rev/min. When switched off, it rotates through 52.0 revolutions before coming to rest. Find the constant angular acceleration (in rad/s2) of the centrifuge.

-62.02πrads/sec^2

Explanation:

A centrifuge in a medical laboratory rotates at an angular speed of 3,550 rev/min. When switched off, it rotates through 52.0 revolutions before coming to rest. Find the constant angular acceleration (in rad/s2) of the centrifuge.

We need to convert to SI unit

9.549rev/ min= 1rad/sec

Then to convert angular speed of 3,550 rev/min to rad/sec

( 1 rad/sec)/9.549rev/min = x/5600rev/min

Then

(3,550 rev/min)/(9.549rev/min)= 371.77rad/sec

=118.4πrad/sec

6.823rad= 1rev

52.0 revolutions = 52×6.823= 354.796rads

= 113πrads

We will use expresion below to calculate our angular acceleration

w^2 - w^2(0)= 2α¢

Where w= angular speed

w(0)= initial angular

If final angular speed= 0

α=-w^2(0)/2¢

α=(-118.4π)^2/(2×113)

=-14018.56/226

-62.02πrads/sec^2

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