2 point Question 9
An object is shot from the ground at 75m/s at an angle of 45° above the horizontal. How high does the object get before beginning its descent?

Before beginning its descent, the object gets 143.5 meters high

Explanation:

Projectile Motion

It's known as the type of motion that experiences an object that is projected near the Earth's surface and moves along a curved path exclusively under the action of gravity.

Being vo the initial speed of the object, θ the initial launch angle, and the acceleration of gravity, then the maximum height reached by the object is:

The object is shot at vo=75 m/s at an angle of θ=45°. The maximum height is calculated below:

Before beginning its descent, the object gets 143.5 meters high

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.

a. vertically

explanation:

i tried it and took the test

if im wrong then we have different tests