B) A car runs at a constant speed of 15 m/s for 300 s and then accelerates uniformly
to a speed of 25 m/s over a period 20 s.
This speed is maintained for 300 s before
the car is brought to rest with uniform
deceleration in 30 s.
1) Sketch the velocity-time graph to
represent the journey described
above.

wavelength divides in half and speed stays the same.

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j