Assume Earth and a cloud layer 0.900 Km above the Earth can be treated as plates of a parallel-plate capacitor. a. If the cloud layer has an area of 2.00 × 104 m2, what is the capacitance?
b. If an electric field strength of 2.0 × 105 N/C causes the air to conduct charge (lightning), what charge can the cloud hold?
c. Describe what must happen to its molecules for air to conduct electricity.
Please Help

(A)-1.96e-10 nanoFarads (B)- 0.03528 C (C)- The flow of electricity is the flow of electrons through a medium. The air has to partially ionize in order to allow for the flow of electrons.Explanation:

(A) Capacitance can be calculated using or . This results in a value of 1.96e-12 nanofarads

(B) The total charge can be calculated using the equation C*V=Q

We have to find the voltage across the capacitor. To do this use the equation E*D=V. This results in a value of 1.8e8 Volts. Plug this value and the capacitance value into the equation C*V=Q. This will result in a value of 0.03528 coulombs of charge.

(C) The flow of electricity is the flow of electrons through a medium. The air has to partially ionize in order to allow for the flow of electrons.

force required to detach it is given by

charges are taken to be fundamental charge

now we have

so above is the minimum distance at which it will detach