A bowling ball weighing 10.0 N is dropped off the top of a 5.00 m tall building. After falling 1.00 m, the book’s kinetic energy is? a. 10.0 J b. 5.00 J c. 40.0 J d. 50.0 J

a. 10.0 J

Explanation:

Given parameters:

Weight of bowling ball  = 10N

Height of building  = 5m

Distance of fall  = 1m

Unknown:

Kinetic energy of the ball  = ?

Solution:

Kinetic energy is the energy due to the motion of a body.

 Mathematically;

          K.E  = mv²

Since this body is falling under gravity;

         K.E  = mgh

 mg = weight of the ball

   h is the height

Insert the parameters and solve;

       K.E  = 10 x 1

       K.E  = 10J

= initial pressure

= final pressure = 2

= initial volume

= final volume = /4

= initial temperature = 20 c = 20 + 273 = 293 k

= final temperature = ?

using the equation