A person dives off the edge of a cliff 56 m above the surface of the sea below. Assuming that air resistance is negligible, how long does the dive last and with what speed does the person enter the water? Round your final answers to the nearest integer.

1. 3 s.

2. 33 m/s

Explanation:

From the question given above, we obtained the following data:

Height (h) = 56 m

1. Determination of the time taken for the person to get to the water.

Height (h) = 56 m

Acceleration due to gravity (g) = 9.8 m/s²

Time taken (t) =?

h = ½gt²

56 = ½ × 9.8 × t²

56 = 4.9 × t²

Divide both side by 4.9

t² = 56/4.9

Take the square root of both side

T = √(56/4.9)

T = 3.3 ≈ 3 s

Therefore, it will take the person approximately 3 s to get to the water.

2. Determination of the velocity with which the diver enters the water.

Initial velocity (u) = 0 m/s

Height (h) = 56 m

Acceleration due to gravity (g) = 9.8 m/s²

Final velocity (v) =?

v² = u² + 2gh

v² = 0² + (2 × 9.8 × 56)

v² = 0 + 1097.6

v² = 1097.6

Take the square root of both side

v = √(1097.6)

v = 33 m/s

Thus, the diver dives into the water with a velocity of 33 m/s.