A football player runs the 40-yard dash (36.58 meters) in 4.43 seconds. If the player starts at rest and uniformly accelerates, A) Calculate the acceleration of the football player. B) Find the final speed of the football player.

a)3.73 m/s^2

b) 16.52 m/s

Explanation:

From

s= ut + 1/2 at^2

Where;

u= initial velocity (object started from rest) = 0 m/s

t= time taken = 4.43 seconds

a= acceleration= the unknown

s= distance= 36.58 m

s= 1/2 at^2

a= 2s/t^2

a= 2 × 36.58/(4.43)^2

a=73.16 /19.62

a = 3.73 m/s^2

From

v= u + at

But u= 0m/s since it started from rest

v= 3.72 × 4.43

v= 16.52 m/s

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