A rock is thrown down at an angle of 25° below horizontal from the top of a building with an initial speed of 12 m/s. The building is 70 m tall. How far from the base of the building does the rock land?

Explanation:

What is the range of a projectile?

the range can be defined as the distance from the point of projection, where the projectile touches the ground again.

given data

∅=25°

initial speed= 12m/s

assuming g= 9.81m/s^2

The expression for the range is given as

R=(u^2sin2∅)/g

substituting we have

R=12^2sin(2*25)/9.81

R=144sin50/9.81

R=144*0.76/9.81

R=110.3/9.81

R=11.24m

the rock will land at 11.24m away from the buiding

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explanation:

no simpler subs form complex ones. synthesise = make