A stone is released from rest from a height of 60 m. How long does it take to hit the ground? 4.4 s
2.3 s
5.2 s
3.5 s

It would take a stone released from a height of 60m, 3.5s to hit the ground.

EQUATION OF MOTION:

The time taken for a stone of height 60m to hit the ground can be calculated by using the following formula of motion:S = ut + ½at²

Where;

S = distance (m)u = initial velocity (m/s)t = time a = acceleration due to gravity (9.8m/s²)Since the stone is released from rest, it would have a initial velocity of 0m/s. 60 = (0×t) + ½ × 9.8 × t²60 = 4.9t²t² = 60 ÷ 4.9t² = 12.24t = √12.24t = 3.5sTherefore, it would take a stone released from a height of 60m, 3.5s to hit the ground.

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Ibelieve the correct answer would be c.

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