*PLEASE HELP* An airplane flying parallel to the ground undergoes two consecutive dis-
placements. The first is 75 km 30.0° west of north, and the second is
155 km 60.0° east of north. What is the total displacement of the
airplane?

9514 1404 393

  172.19 km, N 34.18° E

Explanation:

The turn made at the end of the first leg is 90°, so the total displacement can be found using the Pythagorean theorem.

  d = √(75^2 +155^2) = √29650

  d ≈ 172.19 . . . km

The direction can be found from the angle between the initial leg and the end point. That angle is ...

  α = arctan(155/75) ≈ 64.18°

Then the direction from the starting position to the final position is ...

  -30° +64.18° = 34.18° . . . . east of north

The total displacement of the airplane is ...

  172.19 km, N 34.18° E

there are no correct statementd on the list of choices you provided.

i don't understand. explain it clearly