A 0.28-kg stone is thrown vertically into the air, rising to a height of 4.3 meters. What was the magnitude of the impulse it received from the person tossing the stone

The impulse it received from the person tossing the stone is 2.58 N.s

Explanation:

Given;

mass of the stone, m = 0.28 kg

height risen by the stone in air, h = 4.3 meters

Time taken for the stone to reach 4.3 meters is given by;

Impulse is given as;

J = Ft

where;

force applied on the stone due to its weight

J = (mg)t

J = (0.28 x 9.8)(0.94)

J = 2.58 N.s

Therefore, the impulse it received from the person tossing the stone is 2.58 N.s

explanation:

the masses of the objects and the distance between them