1. A soccer ball is kicked horizontally off a cliff with an initialspeed of 8 m/s and lands 16m from the base of the cliff
a. What is the time of flight of the soccer ball?
b. What is the height of the cliff?

Explanation:

a ) For horizontal displacement

displacement = 16 m

acceleration a = 0

velocity = 8 m /s

time to cover horizontal displacement = time of flight

= displacement / velocity

= 16 / 8 = 2 s

time of flight t = 2 s

b )

for vertical displacement

initial velocity u = 0

time of flight t = 2 s

height h

h = ut + 1/2 g t²

= 0 + .5 x 9.8 x 2²

= 19.6 m

height of cliff = 19.6 m .

the bal will not change its velocity.