A cannon tilted up at a 29o angle fires a cannon ball at 83 m/s from atop a 11-m-high fortress wall. What is the ball's impact speed on the ground below?

v = 84.28 m/s

Explanation:

It is given that,

Initial velocity of a cannon, u = 83 m/s

Angle with which it is fired,

It is fired from a top a 11 m high fortress wall.

Let v is the ball's impact speed on the ground below. It can be calculated using the third equation motion.

So, the ball's impact speed on the ground below is 84.28 m/s.

0 = 0.40 / 0 = 0

= 0.20 = 9.80 ⁄2 =?

=0 , = = 0.20 =0.50 0 0.40 ⁄

=0−122 =0−12(9.80 ⁄2)(0.50)2 =1.2