a race car traveling at 14 m/s accelerates to velocity of 22 m/s over an 11s interval. What distance did the car travel?

Let' start by writing the space-time equation that we'll need for that problem:

s = 1/2*a*t^2 + v0t + s0

where s is the space, a the acceleration, t the time, v0 the initial velocity, s0 the initial space.

In this case we can say that s0 = 0 so the formula will now be:

s = 1/2*a*t^2 + v0t

Let's calculate the acceleration now:

a = Δv/Δt  so 2m/s^2

Now we can calculate the space:

s = 1/2*2m/s^2*11s^2 + 14m/s*11s

s = 11m + 154m = 165 m

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they should be similar or the same

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