What is the power output of an electric motor that lifts a 2.0-kilogram block 15 meters vertically in 6.0
seconds? PLEASE SHOW WORK
1. 5.0 J
2. 5.0 W
3. 49 J
4. 49 W

Power = 49 W

Explanation:

power = work / time (J/t or watt)

Joule or J = kg*/

watt or W = J/s

given:

mass = 2.0 kg

height = 15 m

g = 9.81 m/s2  (assumed)

t = 6 seconds

work = mass*g*h

work = 2.0*9.81*15 = 294.3 kg*/ = 294.3 J

Power = 294.3 J / 6 seconds = 49.1 J/s = 49 W

get the total number of pieces of fruit and divide it by 4 to get the average. the result is the answer to the problem. 14 total number of fruits and there are 4 members. 14 divided by 4 is equals to 3.5.