A coiled telephone cord forms a spiral with 65.0 turns, a diameter of 1.30 cm, and an unstretched length of 65.5 cm. Determine the inductance of one conductor in the unstretched cord.

Explanation:

Given that,

No of turns in a coiled telephone cord is 65

The diameter of the coil, d = 1.3 cm = 0.013 m

Radius, r = 0.0065 m

Unstretched length of the coil, l = 65.5 cm = 0.655 m

We need to find the inductance of one conductor in the unstretched cord. The formula for the inductance is given by :

So, the inductance of one conductor in the unstretched cord is .

answer; i believe the correct answer is (40,000 j) good luck

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