When the charges in the rod are in equilibrium, what is the magnitude EEE of the electric field within the rod

E= vB

Explanation:

If and when the charge on a rod happens to be in equilibrium, then we say that the electric force in conjunction with the magnetic force that is acting on the charge on the rod are both equal and opposite in direction. Mathematically, we say

Fe = Fm, where

Fe = qE and

Fm = qvB

If we substitute and make them equal to one another, we have

qE = qvB, and finally, on simplifying further, we have

E = vB

answer is slate

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