Physics, 09.11.2020 17:20 KBH3298

Se lanza una pelota y regresa al punto de partida 2.5 s después ¿Que altura máxima alcanzara? ¿a que altura se hallaba 1 segundo después del lanzamiento?

Answers: 2

Show answers

Answers

Answer from: niyah2224

a) $y_{max} = 7.7 m$

b) y = 7.4 m

Explanation:

a) La altura máxima que alcanza la pelota se puede encontrar usando la siguiente ecuación:

$y_{max} = y_{0} + v_{0y}t - \frac{1}{2}gt^{2}$ (1)

En donde:

$y_{0}$ : es la altura inicial = 0

$v_{0y}$ : es la velocidad inicial en y

g: es la gravedad = 9.81 m/s²

t: es el tiempo

Primero debemos encontrar la velocidad inicial en y:

$v_{fy} = v_{0y} - gt$

Sabiendo que la velocidad final en y es igual a cero (en la altura máxima), y con t = 1.25 s (la mitad del tiempo total) tenemos:

$v_{0y} = gt = 9.81 m/s^{2}*1.25 s = 12.3 m/s$

Ahora, podemos encontrar la altura máxima:

$y_{max} = v_{0y}t - \frac{1}{2}gt^{2} = 12.3 m/s*1.25 s - \frac{1}{2}9.81 m/s^{2}*(1.25 s)^{2} = 7.7 m$

b) Podemos encontrar la altura cuando t = 1 s con la misma ecuación (1):

$y_{max} = y_{0} + v_{0y}t - \frac{1}{2}gt^{2} = 12.3 m/s*1 s - \frac{1}{2}9.81 m/s^{2}*(1 s)^{2} = 7.4 m$

Por lo tanto, la pelota se encontraba a 7.4 m luego de 1 segundo despúes del lanzamiento.

Espero que te sea de utilidad!

Answer from: Quest

stands for electromotive force and it is measured in volts. despite its name, it is not actually the force in the sense of being a "pushing" or "pulling" (not measured in newtons).an equation that relates emf, ℰ, to a battery's terminal voltage, v, current, i, and internal resistance, r, is ℰ = v + irin this case, the emf can be interpreted as a voltage—a difference in electric potential.i would not say that it would be considered an energy. if emf can be defined as the energy/work per a unit charge from a battery or other electric source, then it is not strictly energy.

Answer from: Quest

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

Another question on Physics

Physics, 22.06.2019 01:40

In all trials, the magnitude of the final velocity for g1 + g2 was less than the magnitude of any initial velocity. as mass increased, what happened to the velocity? the velocity decreased. the velocity increased. the velocity of g1 + g2 could not be measured. the velocity was not affected by the mass increase.

Answers: 1

Answer

Physics, 22.06.2019 02:20

22. the effect of threshold braking is to a cause skids. b. lock wheels. c. prevent locking of wheels. d. increase stopping distance.

Answers: 2

Answer

Physics, 22.06.2019 05:30

Acombination reaction is when two or more combine to form one product. a decomposition reaction is when a substance breaks down into two or more simpler substances in a chemical reaction.

Answers: 1

Answer

Physics, 22.06.2019 11:20

More solar radiation is absorbed by earth’s surface than by

Answers: 1

Answer

You know the right answer?

Se lanza una pelota y regresa al punto de partida 2.5 s después ¿Que altura máxima alcanzara? ¿a que...

Questions