A student with mass (38.0 C) kg rides on a roller coaster with a vertical loop. At the top of the loop the track has a radius of (14.7 B) m and the roller coaster moves at speed of (16.9 A) m/s at the top. Determine the normal force from the seat on the student at the top of the loop. Give your answer in newtons (N) and with 3 significant figures.

the answer would be c. motion and direction

i hope this : )

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

the inner core.

good luck: )

klicker