A cement truck when filled weighs 42 000 N. Calculate its mass

Explanation:we divided the truck weight by 2 since the front tires carry half the truck weight (the question tells us this). In part b) on the other hand, we're dealing with a metal cabinet in the truck box. The normal force applied by the truck box on the metal cabinet is the full weight of the cabinet, hence no need to divide by 2. The weight of the cabinet is being supported by only one thing, namely the truck box, whereas the weight of the truck is being supported by 2 sets of wheels, only one of which is applying static friction to the ground since we assume it's a front wheel drive truck.

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft