A helicopter is dropping a package of rescue supplies to a group of stranded hikers. If it drops the supplies while it is hovering 172m above the hikers, how long does it take to hit the ground?

This question is incomplete

Explanation:

This question is incomplete because of the absence of the average velocity at which the supplies are travelling in air. The formula to be used here if the completed question is obtained is

Average velocity (in m/s) =  distance (m) ÷ time (s)

Since we are looking for the time, then time should be made the subject of the formula

time (in secs) = distance ÷ average velocity

i cant see the choices man

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14