A race car accelerates uniformly from 18.5 m/s to 46.1 m/s in 2.47 seconds. Determine the acceleration of the car and the distance traveled.

79.8 is the answere

I hope this HELP :)

Explanation:

Here, initial velocity is u=18.5m/s and final velocity is v=46.1m/s

Time taken t=2.47s

If a be the acceleration of the car.

Using v=u+at,

46.1=18.5+a(2.47)

⟹ a=11.17m/s

2

If d be the distance traveled by car.

Using formula v

2

−u

2

=2ad,

(46.1)

2

−(18.5)

2

=2(11.17)d

⟹ d=79.8m

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle