A 200 g blob of clay moves with a speed of 10 m/s towards a 300 g cart that is initially at rest. a. What is the momentum of the system before the blob of clay strikes the cart?
b. What must be the momentum of the system after they come together?
c. If the blob of clay sticks to the cart, with what speed will the clay and cart move after they come together?

a. 2 kg*m/s

b.

c. 4 m/s

Explanation:

a. The momentum of the system () before the blob of clay strikes the cart is:

Where:

is the momentum of the blob clay

is the momentum of the car      

Since the car is initially at rest, = 0

b. The momentum of the system after they come together:

Since they come together, =

  (1)

Because we do not have the final speed we can not calculate the final momentum.

c. We can find the speed of the clay and car by conservation of the momentum:

The initial momentum of the system was founded in part "a" (p = 2 kg*m/s), so we have:

Again, when they come together, the final speed is the same:

Now, since we found the final speed we can calculate the momentum of the system after they come together (equation 1):        

I hope it helps you!                  

higher potential

explanation:

because it is in a high speed so it must move into a of high potential