A hydraulic car jack needs to be designed so it can lift a 2903.57 lb car assuming that a person can exert a force of 24.41 lbs. If the piston the person is pushing on had a radius of 3.26 cm, what should the diameter of the piston be that is used to raise the car?

Diameter of the piston would be 0.71 m (71.1 cm)

Explanation:

From the principle of pressure;

=

Let = 2903.57 lb, = 24.41 lbs, = 3.26 cm = 0.0326 m.

=

    = x

    = 0.00334

So that:

=

=

    = 0.3973

= 0.4

The radius of the piston can be determined by:

=

0.3973 = x

=

   = 0.1264

r =

 = 0.3555

r = 0.36 m

Diameter of the piston = 2 x r

                                     = 2 x 0.3555

                                     = 0.711

Diameter of the piston would be 0.71 m (71.1 cm).

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