What is the magnitude and direction of the magnetic force on the bob at the lowest point in its path, if it has a positive 0.250 μC charge and is released from a height of 30.0 cm above its lowest point? The magnetic field strength is 1.50 T.

Explanation:

Given that,

Charge, q = 0.250 μC

It is released from a height of 30 cm or 0.03 m

The magnetic field strength is 1.50 T.

First we find the velocity using the conservation of energy as follows :

Now, the magnetic force is given by :

So, the magnetic force is . Since, the bob is at the lowest point, the direction of the magnetic force at the lowest point is upward.

b) 10 minutes

girls stopped for 10 minutes.