A tiger leaps horizontally from a 6.2 m high rock with a speed of 3.4 m/s. How far from the base of the rock will she land?

First you will have to find how long Tiger stays in the air...since we consider the horizontal motion to be constant, then we have to find it using vertical motion...
y = vot + 1/2at*2
Tiger's vertical motion is 0 to begin with...
6.3 m = 0 + 1/2(9.8 m/s*2)t*2
t = 1.13 s
Second, how far horizontally will Tiger travel in that time...
v = d/t or d = vt = 3.5 m/s(1.13 s) = 4.0 m

Answer8.0m;