A motor with a resistance of 320 is connected to a voltage source. Four amps of current flows in the circuit. What is the voltage of the source?
I

V = 1280 [V]

Explanation:

To solve this problem we must use ohm's law which tells us that the voltage is equal to the product of the resistance by the current.

Therefore we have:

V = I*R

where:

V =  voltage [V] (Units of volts)

I = current = 4 [amp]

R = resistance = 320 [ohms]

V = 4*320

V = 1280 [V]