A coin was flipped in the air and reached a maximum height of 1.5 meters. What was the initial velocity? How long was the coin in the air? Ignore air resistance.

Vi = 5.42 [m/s]

t = 0.55 [s]

Explanation:

To solve this problem we must use the following equation of kinematics.

where:

Vf = final velocity = 0 (At maximum elevation the coin doesn't move)

Vi = initial velocity [m/s]

g = gravity acceleration = 9.81 [m/s²]

y = elevation = 1.5 [m]

Note: The negative sign in the above equation means that the direction of the gravity acceleration is acting against the movement of the coin when it is going up.

0 = (Vi)² - (2*9.81*1.5)

29.43 = (Vi)²

Vi = 5.42 [m/s]

The time we can find it using the next equation also from kinematics.

0 = 5.42 - 9.81*t

t = 5.42/9.81

t = 0.55 [s]

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Explanation:

a.   mass number from atomic number