If you throw a ball straight up with an initial velocity of 16 m/s, how high will it go?

the answer is a)

mark brainliest

attach the statements so i can answer : )

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west