A shot-putter exerts a force of 140 N on a shotput, giving it an acceleration of 19 m/s2. What is the mass of the shot put?

The mass of the shotput is 7.37 Kg.

Explanation:

Mechanical Force

According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:

F = m.a

Where a is the acceleration of the object. If the net force is zero, the object keeps moving at the same speed or keeps at rest (v=0).

A force of 140 N is exerted by a shot-putter on a shotput, which gets an acceleration of 19 m/s^2. We are required to calculate the mass of the shotput.

It can be done by solving the equation for m:

Substituting the given values:

m = 7.37 Kg

The mass of the shotput is 7.37 Kg.

the answer is b ) square root of 5

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