Physics, 16.11.2020 16:30 balancingmist1827

A +4.0 uC charge is placed on the x axis at x= +3.0 m, and a -2.0 uC is located on the y-axis at y= -1.0 m. Point A is on the y axis at y= +4.0 m. Determine the electric potential at point A (relative to zero at the origin).

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Answer from: esuqugip9498

The potential is $V_A = 9600 \ V$

Explanation:

From the question we are told that

The magnitude of the charge is $q_1 = 4 \mu C = 4*10^{-6} \ C$

The position of the charge is $x = + 3.0 \ m$

The magnitude of the second charge is $q_2 = -2.0 \mu C = -2.0 *10^{-6} \ C$

The position is $y_1 = - 1.0 \ m$

The position of point A is $y_2 = + 4.0 \ m$

Generally the electric potential at A due to the first charge is mathematically represented as

$V_a = \frac{k * q_1 }{r_1 }$

Here k is the coulombs constant with value $k = 9*10^{9} \ \ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}$

r_1 is the distance between first charge and a which is mathematically represented as

$r_1 = \sqrt{x^2 + y_2 ^2 }$

=> $r_1 = \sqrt{3^2 + 4 ^2 }$

=> $r_1 = 5 \ m$

$V_a = \frac{9*10^9 * 4*10^{-6} }{5 }$

$V_a = 7200 \ V$

Generally the electric potential at A due to the second charge is mathematically represented as

$V_b = \frac{k * q_2 }{r_2 }$

Here k is the coulombs constant with value $k = 9*10^{9} \ \ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}$

r_2 is the distance between second charge and a which is mathematically represented as

r_2 = y_2 - y

=> r _2 = 4.0 - (-1.0)

=> $r = 5 \ m$

$V_a = \frac{9*10^9 * -2*10^{-6} }{5 }$

$V_a = -3600 \ V$

So the net potential difference at point A due to the charges is mathematically represented as

V_n = V_a + V_b

=> V_n = 7200 - 3600

=> V_n = 3600 V

Generally the net potential difference at the origin due to both charges is mathematically represented as

V_N = V_c + V_d

Here

$V_c = \frac{k * q_1 }{x}$

=> $V_c = \frac{9*10^9 * 4*10^{-6} }{3}$

=> V_c = 12000 V

and

$V_d= \frac{k * q_2 }{y}$

=> $V_c = \frac{9*10^9 * -2*10^{-6} }{1}$

=> V_c =- 18000 V

Generally the net potential difference at the origin is

V_N = 12000 - 18000

=> V_N = -6000

Generally the potential difference at A relative to zero at the origin is mathematically evaluated as

V_A = V_n - V_N

=> V_A = 3600 - (-6000)

=> $V_A = 9600 \ V$

Answer from: Quest

An atom (ours, not carroll's) consists of a positively charged nucleus, surrounded by one or more negatively charged particles called electrons. the positive charges equal the negative charges, so the atom has no overall charge; it is electrically neutral. most of an atom's mass is in its nucleus; the mass of an electron is only 1/1836 the mass of the lightest nucleus, that of hydrogen. although the nucleus is heavy, it is quite small compared with the overall size of an atom. the radius of a typical atom is around 0.1 to 0.25 nanometres (nm), whereas the radius of a nucleus is about 10-6 nm. * if an atom were enlarged to the size of the earth, its nucleus would be only 200 feet in diameter and could easily rest inside a small football stadium.read more on -

Answer from: Quest

option number c is the right answer.

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A +4.0 uC charge is placed on the x axis at x= +3.0 m, and a -2.0 uC is located on the y-axis at y=...

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